### Problem

Given a collection of intervals, merge all overlapping intervals.

For example,

Given [1,3],[2,6],[8,10],[15,18],

return [1,6],[8,10],[15,18].

### Analysis

If End element of an interval is greater than start element of next element, then merge those two intervals and make it as one interval.

### Javascript Code

var Interval = function (s, e) { this.start = s; this.end = e; } function merge(intervals) { if (intervals == null || intervals.length <= 1) return intervals; // sort intervals by using self-defined Comparator intervals.sort(function(a,b) { if(a.start > b.start) { return 1; } else if(a.start < b.start) { return -1; } return 0; }); var result = []; var prev = intervals[0]; for (var i = 1; i < intervals.length; i++) { var curr = intervals[i]; if (prev.end >= curr.start) { // merged case var merged = new Interval(prev.start, Math.max(prev.end, curr.end)); prev = merged; } else { result.push(prev); prev = curr; } } result.push(prev); return result; } var intevs = [new Interval(1,3), new Interval(5,10), new Interval(9,15)];

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